| Message ID | 1612781926-56206-2-git-send-email-luojiaxing@huawei.com (mailing list archive) |
|---|---|
| State | Not Applicable |
| Headers | show |
| Series | irqchip/gic-v3-its: don't set bitmap for LPI which user didn't allocate | expand |
On 2021-02-08 10:58, Luo Jiaxing wrote: > The driver sets the LPI bitmap of device based on > get_count_order(nvecs). > This means that when the number of LPI interrupts does not meet the > power > of two, redundant bits are set in the LPI bitmap. However, when free > interrupt, these redundant bits is not cleared. As a result, device > will > fails to allocate the same numbers of interrupts next time. > > Therefore, clear the redundant bits set in LPI bitmap. > > Fixes: 4615fbc3788d ("genirq/irqdomain: Don't try to free an interrupt > that has no mapping") > > Signed-off-by: Luo Jiaxing <luojiaxing@huawei.com> > --- > drivers/irqchip/irq-gic-v3-its.c | 4 ++++ > 1 file changed, 4 insertions(+) > > diff --git a/drivers/irqchip/irq-gic-v3-its.c > b/drivers/irqchip/irq-gic-v3-its.c > index ed46e60..027f7ef 100644 > --- a/drivers/irqchip/irq-gic-v3-its.c > +++ b/drivers/irqchip/irq-gic-v3-its.c > @@ -3435,6 +3435,10 @@ static int its_alloc_device_irq(struct > its_device *dev, int nvecs, irq_hw_number > > *hwirq = dev->event_map.lpi_base + idx; > > + bitmap_clear(dev->event_map.lpi_map, > + idx + nvecs, > + roundup_pow_of_two(nvecs) - nvecs); > + > return 0; > } What makes you think that the remaining LPIs are free to be released? Even if the end-point has request a non-po2 number of MSIs, it could very well rely on the the rest of it to be available (specially in the case of PCI Multi-MSI). Have a look at the thread pointed out by John for a potential fix. Thanks, M.
On 2021/2/8 19:59, Marc Zyngier wrote: > On 2021-02-08 10:58, Luo Jiaxing wrote: >> The driver sets the LPI bitmap of device based on >> get_count_order(nvecs). >> This means that when the number of LPI interrupts does not meet the >> power >> of two, redundant bits are set in the LPI bitmap. However, when free >> interrupt, these redundant bits is not cleared. As a result, device will >> fails to allocate the same numbers of interrupts next time. >> >> Therefore, clear the redundant bits set in LPI bitmap. >> >> Fixes: 4615fbc3788d ("genirq/irqdomain: Don't try to free an interrupt >> that has no mapping") >> >> Signed-off-by: Luo Jiaxing <luojiaxing@huawei.com> >> --- >> drivers/irqchip/irq-gic-v3-its.c | 4 ++++ >> 1 file changed, 4 insertions(+) >> >> diff --git a/drivers/irqchip/irq-gic-v3-its.c >> b/drivers/irqchip/irq-gic-v3-its.c >> index ed46e60..027f7ef 100644 >> --- a/drivers/irqchip/irq-gic-v3-its.c >> +++ b/drivers/irqchip/irq-gic-v3-its.c >> @@ -3435,6 +3435,10 @@ static int its_alloc_device_irq(struct >> its_device *dev, int nvecs, irq_hw_number >> >> *hwirq = dev->event_map.lpi_base + idx; >> >> + bitmap_clear(dev->event_map.lpi_map, >> + idx + nvecs, >> + roundup_pow_of_two(nvecs) - nvecs); >> + >> return 0; >> } > > What makes you think that the remaining LPIs are free to be released? I think that the LPI bitmap is used to mark the valid LPI interrupts allocated to the PCIe device. Therefore, for the remaining LPIs, the ITS can reserve entries in the ITT table, but the bitmap does not need to be set. Maybe my understanding is wrong, and I'm a little confused about the function of this bitmap. > Even if the end-point has request a non-po2 number of MSIs, it could > very well rely on the the rest of it to be available (specially in the > case of PCI Multi-MSI). yes, you are right. But for Multi-MSI, does it mean that one PCIE device can own several MSI interrupts? Another question, is it possible for module driver to use these remaining LPIs? For example, in my case I allcoate 32 MSI with 16 affi-IRQ in it. MSI can only offer 20 MSIs because online CPU number is 4 and it create 20 msi desc then. ITS create a its device for this PCIe device and generate a ITT tabel for 32 MSIs. so in MSI, it provide 20 valid MSIs, but in ITS, lpi bitmap show that 32 MSI is allocated. This logic is a bit strange and a little incomprehensible. > > Have a look at the thread pointed out by John for a potential fix. Sorry for missing that, I think it can fix my issue too, let me test it later. Thanks jiaxing > > Thanks, > > M.
diff --git a/drivers/irqchip/irq-gic-v3-its.c b/drivers/irqchip/irq-gic-v3-its.c index ed46e60..027f7ef 100644 --- a/drivers/irqchip/irq-gic-v3-its.c +++ b/drivers/irqchip/irq-gic-v3-its.c @@ -3435,6 +3435,10 @@ static int its_alloc_device_irq(struct its_device *dev, int nvecs, irq_hw_number *hwirq = dev->event_map.lpi_base + idx; + bitmap_clear(dev->event_map.lpi_map, + idx + nvecs, + roundup_pow_of_two(nvecs) - nvecs); + return 0; }
The driver sets the LPI bitmap of device based on get_count_order(nvecs). This means that when the number of LPI interrupts does not meet the power of two, redundant bits are set in the LPI bitmap. However, when free interrupt, these redundant bits is not cleared. As a result, device will fails to allocate the same numbers of interrupts next time. Therefore, clear the redundant bits set in LPI bitmap. Fixes: 4615fbc3788d ("genirq/irqdomain: Don't try to free an interrupt that has no mapping") Signed-off-by: Luo Jiaxing <luojiaxing@huawei.com> --- drivers/irqchip/irq-gic-v3-its.c | 4 ++++ 1 file changed, 4 insertions(+)