[2/4] ARM: pmu: reject duplicate PMU registrations

Commit Message

Mark Rutland June 13, 2011, 9:35 a.m. UTC

Currently, the PMU reservation framework allows for multiple PMUs of
the same type to register themselves. This can lead to a bug with the
sequence:

register_pmu(pmu1);
reserve_pmu(pmu_type);
register_pmu(pmu2);
release_pmu(pmu1);

Here, pmu1 cannot be released, and pmu2 cannot be reserved.

This patch modifies register_pmu to reject registrations where a PMU is
already present, preventing this problem. PMUs which can have multiple
instances should not use the PMU reservation framework.

Signed-off-by: Mark Rutland <[e-mail]>
Acked-By: Jamie Iles <[e-mail]>
Acked-By: Will Deacon <[e-mail]>
---
 arch/arm/kernel/pmu.c |   12 ++++++------
 1 files changed, 6 insertions(+), 6 deletions(-)

Patch

diff --git a/arch/arm/kernel/pmu.c b/arch/arm/kernel/pmu.c
index 87942b9..de6b1b0 100644
--- a/arch/arm/kernel/pmu.c
+++ b/arch/arm/kernel/pmu.c
@@ -34,13 +34,13 @@  static int __devinit pmu_register(struct platform_device *pdev,
 		return -EINVAL;
 	}
 
-	if (pmu_devices[type])
-		pr_warning("registering new PMU device type %d overwrites "
-				"previous registration!\n", type);
-	else
-		pr_info("registered new PMU device of type %d\n",
-				type);
+	if (pmu_devices[type]) {
+		pr_warning("rejecting duplicate registration of PMU device "
+			"type %d.", type);
+		return -ENOSPC;
+	}
 
+	pr_info("registered new PMU device of type %d\n", type);
 	pmu_devices[type] = pdev;
 	return 0;
 }