Message ID | 20141121123559.GF23177@e105550-lin.cambridge.arm.com (mailing list archive) |
---|---|
State | New, archived |
Headers | show |
On 21 November 2014 at 13:35, Morten Rasmussen <morten.rasmussen@arm.com> wrote: > On Mon, Nov 03, 2014 at 04:54:42PM +0000, Vincent Guittot wrote: [snip] >> The average running time of RT tasks is used to estimate the remaining compute >> @@ -5801,19 +5801,12 @@ static unsigned long scale_rt_capacity(int cpu) >> >> total = sched_avg_period() + delta; >> >> - if (unlikely(total < avg)) { >> - /* Ensures that capacity won't end up being negative */ >> - available = 0; >> - } else { >> - available = total - avg; >> - } >> + used = div_u64(avg, total); > > I haven't looked through all the details of the rt avg tracking, but if > 'used' is in the range [0..SCHED_CAPACITY_SCALE], I believe it should > work. Is it guaranteed that total > 0 so we don't get division by zero? static inline u64 sched_avg_period(void) { return (u64)sysctl_sched_time_avg * NSEC_PER_MSEC / 2; } > > It does get a slightly more complicated if we want to figure out the > available capacity at the current frequency (current < max) later. Say, > rt eats 25% of the compute capacity, but the current frequency is only > 50%. In that case get: > > curr_avail_capacity = (arch_scale_cpu_capacity() * > (arch_scale_freq_capacity() - (SCHED_SCALE_CAPACITY - scale_rt_capacity()))) > >> SCHED_CAPACITY_SHIFT You don't have to be so complicated but simply need to do: curr_avail_capacity for CFS = (capacity_of(CPU) * arch_scale_freq_capacity()) >> SCHED_CAPACITY_SHIFT capacity_of(CPU) = 600 is the max available capacity for CFS tasks once we have removed the 25% of capacity that is used by RT tasks arch_scale_freq_capacity = 512 because we currently run at 50% of max freq so curr_avail_capacity for CFS = 300 Vincent > > With numbers assuming arch_scale_cpu_capacity() = 800: > > curr_avail_capacity = 800 * (512 - (1024 - 758)) >> 10 = 200 > > Which isn't actually that bad. Anyway, it isn't needed until we start > invovling energy models. > >> >> - if (unlikely((s64)total < SCHED_CAPACITY_SCALE)) >> - total = SCHED_CAPACITY_SCALE; >> + if (likely(used < SCHED_CAPACITY_SCALE)) >> + return SCHED_CAPACITY_SCALE - used; >> >> - total >>= SCHED_CAPACITY_SHIFT; >> - >> - return div_u64(available, total); >> + return 1; >> } >>
On Mon, Nov 24, 2014 at 02:24:00PM +0000, Vincent Guittot wrote: > On 21 November 2014 at 13:35, Morten Rasmussen <morten.rasmussen@arm.com> wrote: > > On Mon, Nov 03, 2014 at 04:54:42PM +0000, Vincent Guittot wrote: > > [snip] > > >> The average running time of RT tasks is used to estimate the remaining compute > >> @@ -5801,19 +5801,12 @@ static unsigned long scale_rt_capacity(int cpu) > >> > >> total = sched_avg_period() + delta; > >> > >> - if (unlikely(total < avg)) { > >> - /* Ensures that capacity won't end up being negative */ > >> - available = 0; > >> - } else { > >> - available = total - avg; > >> - } > >> + used = div_u64(avg, total); > > > > I haven't looked through all the details of the rt avg tracking, but if > > 'used' is in the range [0..SCHED_CAPACITY_SCALE], I believe it should > > work. Is it guaranteed that total > 0 so we don't get division by zero? > > static inline u64 sched_avg_period(void) > { > return (u64)sysctl_sched_time_avg * NSEC_PER_MSEC / 2; > } > I see. > > > > It does get a slightly more complicated if we want to figure out the > > available capacity at the current frequency (current < max) later. Say, > > rt eats 25% of the compute capacity, but the current frequency is only > > 50%. In that case get: > > > > curr_avail_capacity = (arch_scale_cpu_capacity() * > > (arch_scale_freq_capacity() - (SCHED_SCALE_CAPACITY - scale_rt_capacity()))) > > >> SCHED_CAPACITY_SHIFT > > You don't have to be so complicated but simply need to do: > curr_avail_capacity for CFS = (capacity_of(CPU) * > arch_scale_freq_capacity()) >> SCHED_CAPACITY_SHIFT > > capacity_of(CPU) = 600 is the max available capacity for CFS tasks > once we have removed the 25% of capacity that is used by RT tasks > arch_scale_freq_capacity = 512 because we currently run at 50% of max freq > > so curr_avail_capacity for CFS = 300 I don't think that is correct. It is at least not what I had in mind. capacity_orig_of(cpu) = 800, we run at 50% frequency which means: curr_capacity = capacity_orig_of(cpu) * arch_scale_freq_capacity() >> SCHED_CAPACITY_SHIFT = 400 So the total capacity at the current frequency (50%) is 400, without considering RT. scale_rt_capacity() is frequency invariant, so it takes away capacity_orig_of(cpu) - capacity_of(cpu) = 200 worth of capacity for RT. We need to subtract that from the current capacity to get the available capacity at the current frequency. curr_available_capacity = curr_capacity - (capacity_orig_of(cpu) - capacity_of(cpu)) = 200 In other words, 800 is the max capacity, we are currently running at 50% frequency, which gives us 400. RT takes away 25% of 800 (frequency-invariant) from the 400, which leaves us with 200 left for CFS tasks at the current frequency. In your calculations you subtract the RT load before computing the current capacity using arch_scale_freq_capacity(), where I think it should be done after. You find the amount spare capacity you would have at the maximum frequency when RT has been subtracted and then scale the result by frequency which means indirectly scaling the RT load contribution again (the rt avg has already been scaled). So instead of taking away 200 of the 400 (current capacity @ 50% frequency), it only takes away 100 which isn't right. scale_rt_capacity() is frequency-invariant, so if the RT load is 50% and the frequency is 50%, there are no spare cycles left. curr_avail_capacity should be 0. But using your expression above you would get capacity_of(cpu) = 400 after removing RT, arch_scale_freq_capacity = 512 and you get 200. I don't think that is right. Morten
On 24 November 2014 at 18:05, Morten Rasmussen <morten.rasmussen@arm.com> wrote: > On Mon, Nov 24, 2014 at 02:24:00PM +0000, Vincent Guittot wrote: >> On 21 November 2014 at 13:35, Morten Rasmussen <morten.rasmussen@arm.com> wrote: >> > On Mon, Nov 03, 2014 at 04:54:42PM +0000, Vincent Guittot wrote: >> >> [snip] >> >> >> The average running time of RT tasks is used to estimate the remaining compute >> >> @@ -5801,19 +5801,12 @@ static unsigned long scale_rt_capacity(int cpu) >> >> >> >> total = sched_avg_period() + delta; >> >> >> >> - if (unlikely(total < avg)) { >> >> - /* Ensures that capacity won't end up being negative */ >> >> - available = 0; >> >> - } else { >> >> - available = total - avg; >> >> - } >> >> + used = div_u64(avg, total); >> > >> > I haven't looked through all the details of the rt avg tracking, but if >> > 'used' is in the range [0..SCHED_CAPACITY_SCALE], I believe it should >> > work. Is it guaranteed that total > 0 so we don't get division by zero? >> >> static inline u64 sched_avg_period(void) >> { >> return (u64)sysctl_sched_time_avg * NSEC_PER_MSEC / 2; >> } >> > > I see. > >> > >> > It does get a slightly more complicated if we want to figure out the >> > available capacity at the current frequency (current < max) later. Say, >> > rt eats 25% of the compute capacity, but the current frequency is only >> > 50%. In that case get: >> > >> > curr_avail_capacity = (arch_scale_cpu_capacity() * >> > (arch_scale_freq_capacity() - (SCHED_SCALE_CAPACITY - scale_rt_capacity()))) >> > >> SCHED_CAPACITY_SHIFT >> >> You don't have to be so complicated but simply need to do: >> curr_avail_capacity for CFS = (capacity_of(CPU) * >> arch_scale_freq_capacity()) >> SCHED_CAPACITY_SHIFT >> >> capacity_of(CPU) = 600 is the max available capacity for CFS tasks >> once we have removed the 25% of capacity that is used by RT tasks >> arch_scale_freq_capacity = 512 because we currently run at 50% of max freq >> >> so curr_avail_capacity for CFS = 300 > > I don't think that is correct. It is at least not what I had in mind. > > capacity_orig_of(cpu) = 800, we run at 50% frequency which means: > > curr_capacity = capacity_orig_of(cpu) * arch_scale_freq_capacity() > >> SCHED_CAPACITY_SHIFT > = 400 > > So the total capacity at the current frequency (50%) is 400, without > considering RT. scale_rt_capacity() is frequency invariant, so it takes > away capacity_orig_of(cpu) - capacity_of(cpu) = 200 worth of capacity > for RT. We need to subtract that from the current capacity to get the > available capacity at the current frequency. > > curr_available_capacity = curr_capacity - (capacity_orig_of(cpu) - > capacity_of(cpu)) = 200 you're right, this one looks good to me too > > In other words, 800 is the max capacity, we are currently running at 50% > frequency, which gives us 400. RT takes away 25% of 800 > (frequency-invariant) from the 400, which leaves us with 200 left for > CFS tasks at the current frequency. > > In your calculations you subtract the RT load before computing the > current capacity using arch_scale_freq_capacity(), where I think it > should be done after. You find the amount spare capacity you would have > at the maximum frequency when RT has been subtracted and then scale the > result by frequency which means indirectly scaling the RT load > contribution again (the rt avg has already been scaled). So instead of > taking away 200 of the 400 (current capacity @ 50% frequency), it only > takes away 100 which isn't right. > > scale_rt_capacity() is frequency-invariant, so if the RT load is 50% and > the frequency is 50%, there are no spare cycles left. > curr_avail_capacity should be 0. But using your expression above you > would get capacity_of(cpu) = 400 after removing RT, > arch_scale_freq_capacity = 512 and you get 200. I don't think that is > right. > > Morten > -- > To unsubscribe from this list: send the line "unsubscribe linux-kernel" in > the body of a message to majordomo@vger.kernel.org > More majordomo info at http://vger.kernel.org/majordomo-info.html > Please read the FAQ at http://www.tux.org/lkml/
On Tue, Nov 25, 2014 at 01:48:02PM +0000, Vincent Guittot wrote: > On 24 November 2014 at 18:05, Morten Rasmussen <morten.rasmussen@arm.com> wrote: > > On Mon, Nov 24, 2014 at 02:24:00PM +0000, Vincent Guittot wrote: > >> On 21 November 2014 at 13:35, Morten Rasmussen <morten.rasmussen@arm.com> wrote: > >> > On Mon, Nov 03, 2014 at 04:54:42PM +0000, Vincent Guittot wrote: > >> > >> [snip] > >> > >> >> The average running time of RT tasks is used to estimate the remaining compute > >> >> @@ -5801,19 +5801,12 @@ static unsigned long scale_rt_capacity(int cpu) > >> >> > >> >> total = sched_avg_period() + delta; > >> >> > >> >> - if (unlikely(total < avg)) { > >> >> - /* Ensures that capacity won't end up being negative */ > >> >> - available = 0; > >> >> - } else { > >> >> - available = total - avg; > >> >> - } > >> >> + used = div_u64(avg, total); > >> > > >> > I haven't looked through all the details of the rt avg tracking, but if > >> > 'used' is in the range [0..SCHED_CAPACITY_SCALE], I believe it should > >> > work. Is it guaranteed that total > 0 so we don't get division by zero? > >> > >> static inline u64 sched_avg_period(void) > >> { > >> return (u64)sysctl_sched_time_avg * NSEC_PER_MSEC / 2; > >> } > >> > > > > I see. > > > >> > > >> > It does get a slightly more complicated if we want to figure out the > >> > available capacity at the current frequency (current < max) later. Say, > >> > rt eats 25% of the compute capacity, but the current frequency is only > >> > 50%. In that case get: > >> > > >> > curr_avail_capacity = (arch_scale_cpu_capacity() * > >> > (arch_scale_freq_capacity() - (SCHED_SCALE_CAPACITY - scale_rt_capacity()))) > >> > >> SCHED_CAPACITY_SHIFT > >> > >> You don't have to be so complicated but simply need to do: > >> curr_avail_capacity for CFS = (capacity_of(CPU) * > >> arch_scale_freq_capacity()) >> SCHED_CAPACITY_SHIFT > >> > >> capacity_of(CPU) = 600 is the max available capacity for CFS tasks > >> once we have removed the 25% of capacity that is used by RT tasks > >> arch_scale_freq_capacity = 512 because we currently run at 50% of max freq > >> > >> so curr_avail_capacity for CFS = 300 > > > > I don't think that is correct. It is at least not what I had in mind. > > > > capacity_orig_of(cpu) = 800, we run at 50% frequency which means: > > > > curr_capacity = capacity_orig_of(cpu) * arch_scale_freq_capacity() > > >> SCHED_CAPACITY_SHIFT > > = 400 > > > > So the total capacity at the current frequency (50%) is 400, without > > considering RT. scale_rt_capacity() is frequency invariant, so it takes > > away capacity_orig_of(cpu) - capacity_of(cpu) = 200 worth of capacity > > for RT. We need to subtract that from the current capacity to get the > > available capacity at the current frequency. > > > > curr_available_capacity = curr_capacity - (capacity_orig_of(cpu) - > > capacity_of(cpu)) = 200 > > you're right, this one looks good to me too Okay, thanks for confirming. It doesn't affect this patch set anyway, I just wanted to be sure that I got all the scaling factors right :)
diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c index 6fd5ac6..921b174 100644 --- a/kernel/sched/fair.c +++ b/kernel/sched/fair.c @@ -2277,8 +2277,6 @@ static u32 __compute_runnable_contrib(u64 n) return contrib + runnable_avg_yN_sum[n]; } -unsigned long __weak arch_scale_freq_capacity(struct sched_domain *sd, int cpu); - /* * We can represent the historical contribution to runnable average as