@@ -3968,6 +3968,11 @@ out:
return dropped_extents;
}
+static u64 calc_csum_metadata_size(struct inode *inode, u64 num_bytes)
+{
+ return num_bytes >>= 3;
+}
+
int btrfs_delalloc_reserve_metadata(struct inode *inode, u64 num_bytes)
{
struct btrfs_root *root = BTRFS_I(inode)->root;
@@ -3990,21 +3995,11 @@ int btrfs_delalloc_reserve_metadata(struct inode *inode, u64 num_bytes)
BTRFS_I(inode)->reserved_extents;
BTRFS_I(inode)->reserved_extents += nr_extents;
- /* For checksums we'll just reserve 2 leaves worth of metadata
- * and hope that works out right.
- *
- * NOTE:
- * The more correct way to do this would be to figure out how
- * much space we are going to write and figure out how many
- * checksums that comes out to and then adjust whenever we cross
- * a leafsize barrier. But thats a huge pain in the ass, so
- * wing it and hope it comes out right :).
- */
- nr_extents += nr_extents * 2;
to_reserve = btrfs_calc_trans_metadata_size(root, nr_extents);
}
spin_unlock(&BTRFS_I(inode)->lock);
+ to_reserve += calc_csum_metadata_size(inode, num_bytes);
ret = reserve_metadata_bytes(NULL, root, block_rsv, to_reserve, 1);
if (ret) {
unsigned dropped;
@@ -4031,8 +4026,7 @@ void btrfs_delalloc_release_metadata(struct inode *inode, u64 num_bytes)
num_bytes = ALIGN(num_bytes, root->sectorsize);
dropped = drop_outstanding_extent(inode);
- /* See btrfs_delalloc_reserve_metadata for an explanation */
- dropped += dropped * 2;
+ to_free = calc_csum_metadata_size(inode, num_bytes);
if (dropped > 0)
to_free += btrfs_calc_trans_metadata_size(root, dropped);
This just switches us back to the old way of doing csum calculations. It is broken, but less broken than what I fixed it with, so revert it and I'll come up with something more correct for later. Thanks, Signed-off-by: Josef Bacik <josef@redhat.com> --- fs/btrfs/extent-tree.c | 20 +++++++------------- 1 files changed, 7 insertions(+), 13 deletions(-)