=====
// create a file sharing the exactly same extent
$ dd if=/dev/urandom of=/mnt/file bs=4k count=1
$ sync
$ cloner -s 0 -d 4096 -l 4096 /mnt/file /mnt/file // cloner from xfstest
$ sync
$ filefrag -v
Filesystem type is: 9123683e
File size of /mnt/file is 8192 (2 blocks of 4096 bytes)
ext: logical_offset: physical_offset: length: expected: flags:
0: 0.. 0: 3410.. 3410: 1: shared
1: 1.. 1: 3410.. 3410: 1: 3411: last,shared,eof
/mnt/file 2 extents found
// there are two backrefs
$ btrfs inspect-internal dump-tree $DEV | grep -A 3 "$((3410*4096)) EXTENT_ITEM"
item 12 key (13967360 EXTENT_ITEM 4096) itemoff 15449 itemsize 82
refs 2 gen 250 flags DATA
extent data backref root FS_TREE objectid 268 offset 4096 count 1
extent data backref root FS_TREE objectid 268 offset 0 count 1
$ btrfs inspect-internal logical-resolve -P $((3410*4096)) /mnt
inode 268 offset 4096 root 5
inode 268 offset 0 root 5
inode 268 offset 4096 root 5 // Duplicate
(Or, see 004.full of xfstest for more complex case.)
=====
This problem is related to resolving indirect ref.
Related call stack is as below:
btrfs_ioctl_logical_to_ino()
- iterate_extent_inodes_from_logical()
- extent_from_logical()
- iterate_extent_inodes()
- btrfs_find_all_leafs()
- find_parent_nodes() // collect ref and root info
- add_delayed_refs()
- add_inline_refs()
- resolve_indirect_refs()
- resolve_indirect_ref()
- add_all_parents()
In above example, two indirect backrefs of EXTENT_DATA
((268 EXTENT_DATA 0), (268 EXTENT_DATA 4096)) will be added in rb_tree
(descending order) in add_inline_refs(). They will be resolved in
add_all_parents() in the end. However, add_all_parents() will search all
EXTENT_DATA item of the root larger than the given offset which point to
the target extent position each time.
This is needed since backref may be referenced several time within a
file (e.g. when extent is split), but could make duplicate entries.
So, in above case, (268 EXTENT_DATA 4096) returns
"inode 268 offset 4096 root 5" and (268 EXTENT_DATA 0) returns
"inode 268 offset 4096 root 0" and "inode 268 offset 4096 root 5".
Fix this problem by only searching the key with the lowest offset when
ref's rootid and key objectid is the same. In order to this, sort entry
in rb_tree ascending order (by swapping argument order in
prelim_ref_compare() in prelim_ref_insert()) and skip call of
resolve_indirect_ref() when rootid/key objectid matches the previous search.
With this patch, logical-resolve will return correct entries:
$ btrfs inspect-internal logical-resolve -P $((3410*4096)) /mnt
inode 268 offset 0 root 5
inode 268 offset 4096 root 5
Note that find_parent_nodes() is also used in some other places,
but they should not be affected by this patch as stated below:
- send/scrub (through iterate_extent_inodes())
- can work correctly with or without duplicate refs
- qgroup (through btrfs_find_all_roots())
- use only root info and not ref
- snapshot aware defrag (through iterate_extent_inodes_from_logical())
- currently dead code and not used
Signed-off-by: Misono Tomohiro <misono.tomohiro@jp.fujitsu.com>
---
fs/btrfs/backref.c | 10 ++++++++--
1 file changed, 8 insertions(+), 2 deletions(-)
@@ -237,7 +237,7 @@ static void prelim_ref_insert(const struct btrfs_fs_info *fs_info,
while (*p) {
parent = *p;
ref = rb_entry(parent, struct prelim_ref, rbnode);
- result = prelim_ref_compare(ref, newref);
+ result = prelim_ref_compare(newref, ref);
if (result < 0) {
p = &(*p)->rb_left;
} else if (result > 0) {
@@ -612,6 +612,8 @@ static int resolve_indirect_refs(struct btrfs_fs_info *fs_info,
{
int err;
int ret = 0;
+ u64 prev_rootid = 0;
+ u64 prev_objectid = 0;
struct ulist *parents;
struct ulist_node *node;
struct ulist_iterator uiter;
@@ -640,10 +642,14 @@ static int resolve_indirect_refs(struct btrfs_fs_info *fs_info,
rb_erase(&ref->rbnode, &preftrees->indirect.root);
preftrees->indirect.count--;
- if (ref->count == 0) {
+ if (ref->count == 0 ||
+ (prev_rootid == ref->root_id &&
+ prev_objectid == ref->key_for_search.objectid)) {
free_pref(ref);
continue;
}
+ prev_rootid = ref->root_id;
+ prev_objectid = ref->key_for_search.objectid;
if (sc && sc->root_objectid &&
ref->root_id != sc->root_objectid) {