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[2/3] target/s390x: Fix the "ignored match" case in VSTRS

Message ID 20230804233748.218935-3-iii@linux.ibm.com (mailing list archive)
State New, archived
Headers show
Series target/s390x: Fix the "ignored match" case in VSTRS | expand

Commit Message

Ilya Leoshkevich Aug. 4, 2023, 11:03 p.m. UTC
Currently the emulation of VSTRS recognizes partial matches in presence
of \0 in the haystack, which, according to PoP, is not correct:

    If the ZS flag is one and a zero byte was detected
    in the second operand, then there can not be a
    partial match ...

Add a check for this. While at it, fold a number of explicitly handled
special cases into the generic logic.

Cc: qemu-stable@nongnu.org
Reported-by: Claudio Fontana <cfontana@suse.de>
Closes: https://lists.gnu.org/archive/html/qemu-devel/2023-08/msg00633.html
Fixes: 1d706f314191 ("target/s390x: vxeh2: vector string search")
Signed-off-by: Ilya Leoshkevich <iii@linux.ibm.com>
---
 target/s390x/tcg/vec_string_helper.c | 54 +++++++++-------------------
 1 file changed, 17 insertions(+), 37 deletions(-)

Comments

David Hildenbrand Aug. 5, 2023, 8:02 a.m. UTC | #1
On 05.08.23 01:03, Ilya Leoshkevich wrote:
> Currently the emulation of VSTRS recognizes partial matches in presence
> of \0 in the haystack, which, according to PoP, is not correct:
> 
>      If the ZS flag is one and a zero byte was detected
>      in the second operand, then there can not be a
>      partial match ...
> 
> Add a check for this. While at it, fold a number of explicitly handled
> special cases into the generic logic.

Can we split that off? Or doesn't it make sense to split it off after 
fixing the issue?
Claudio Fontana Aug. 6, 2023, 12:54 p.m. UTC | #2
On 8/5/23 01:03, Ilya Leoshkevich wrote:
> Currently the emulation of VSTRS recognizes partial matches in presence
> of \0 in the haystack, which, according to PoP, is not correct:
> 
>     If the ZS flag is one and a zero byte was detected
>     in the second operand, then there can not be a
>     partial match ...
> 
> Add a check for this. While at it, fold a number of explicitly handled
> special cases into the generic logic.
> 
> Cc: qemu-stable@nongnu.org
> Reported-by: Claudio Fontana <cfontana@suse.de>
> Closes: https://lists.gnu.org/archive/html/qemu-devel/2023-08/msg00633.html
> Fixes: 1d706f314191 ("target/s390x: vxeh2: vector string search")
> Signed-off-by: Ilya Leoshkevich <iii@linux.ibm.com>

verified that it fixes the problem I encountered,

Tested-by: Claudio Fontana <cfontana@suse.de>

> ---
>  target/s390x/tcg/vec_string_helper.c | 54 +++++++++-------------------
>  1 file changed, 17 insertions(+), 37 deletions(-)
> 
> diff --git a/target/s390x/tcg/vec_string_helper.c b/target/s390x/tcg/vec_string_helper.c
> index 9b85becdfbf..a19f429768f 100644
> --- a/target/s390x/tcg/vec_string_helper.c
> +++ b/target/s390x/tcg/vec_string_helper.c
> @@ -474,9 +474,9 @@ DEF_VSTRC_CC_RT_HELPER(32)
>  static int vstrs(S390Vector *v1, const S390Vector *v2, const S390Vector *v3,
>                   const S390Vector *v4, uint8_t es, bool zs)
>  {
> -    int substr_elen, substr_0, str_elen, i, j, k, cc;
> +    int substr_elen, i, j, k, cc;
>      int nelem = 16 >> es;
> -    bool eos = false;
> +    int str_leftmost_0;
>  
>      substr_elen = s390_vec_read_element8(v4, 7) >> es;
>  
> @@ -498,47 +498,20 @@ static int vstrs(S390Vector *v1, const S390Vector *v2, const S390Vector *v3,
>      }
>  
>      /* If ZS, look for eos in the searched string. */
> +    str_leftmost_0 = nelem;
>      if (zs) {
>          for (k = 0; k < nelem; k++) {
>              if (s390_vec_read_element(v2, k, es) == 0) {
> -                eos = true;
> +                str_leftmost_0 = k;
>                  break;
>              }
>          }
> -        str_elen = k;
> -    } else {
> -        str_elen = nelem;
>      }
>  
> -    substr_0 = s390_vec_read_element(v3, 0, es);
> -
> -    for (k = 0; ; k++) {
> -        for (; k < str_elen; k++) {
> -            if (s390_vec_read_element(v2, k, es) == substr_0) {
> -                break;
> -            }
> -        }
> -
> -        /* If we reached the end of the string, no match. */
> -        if (k == str_elen) {
> -            cc = eos; /* no match (with or without zero char) */
> -            goto done;
> -        }
> -
> -        /* If the substring is only one char, match. */
> -        if (substr_elen == 1) {
> -            cc = 2; /* full match */
> -            goto done;
> -        }
> -
> -        /* If the match begins at the last char, we have a partial match. */
> -        if (k == str_elen - 1) {
> -            cc = 3; /* partial match */
> -            goto done;
> -        }
> -
> +    cc = str_leftmost_0 == nelem ? 0 : 1;  /* No match. */
> +    for (k = 0; k < nelem; k++) {
>          i = MIN(nelem, k + substr_elen);
> -        for (j = k + 1; j < i; j++) {
> +        for (j = k; j < i; j++) {
>              uint32_t e2 = s390_vec_read_element(v2, j, es);
>              uint32_t e3 = s390_vec_read_element(v3, j - k, es);
>              if (e2 != e3) {
> @@ -546,9 +519,16 @@ static int vstrs(S390Vector *v1, const S390Vector *v2, const S390Vector *v3,
>              }
>          }
>          if (j == i) {
> -            /* Matched up until "end". */
> -            cc = i - k == substr_elen ? 2 : 3; /* full or partial match */
> -            goto done;
> +            /* All elements matched. */
> +            if (k > str_leftmost_0) {
> +                cc = 1;  /* Ignored match. */
> +                k = nelem;
> +            } else if (i - k == substr_elen) {
> +                cc = 2;  /* Full match. */
> +            } else {
> +                cc = 3;  /* Partial match. */
> +            }
> +            break;
>          }
>      }
>
Ilya Leoshkevich Aug. 7, 2023, 8:10 a.m. UTC | #3
On Sat, 2023-08-05 at 10:02 +0200, David Hildenbrand wrote:
> On 05.08.23 01:03, Ilya Leoshkevich wrote:
> > Currently the emulation of VSTRS recognizes partial matches in
> > presence
> > of \0 in the haystack, which, according to PoP, is not correct:
> > 
> >      If the ZS flag is one and a zero byte was detected
> >      in the second operand, then there can not be a
> >      partial match ...
> > 
> > Add a check for this. While at it, fold a number of explicitly
> > handled
> > special cases into the generic logic.
> 
> Can we split that off? Or doesn't it make sense to split it off after
> fixing the issue?

I could do this if this is important, e.g., for stable, but I came to
the conclusion that I needed to get rid of the special cases after I
had to add the new check to more than one place.
David Hildenbrand Aug. 23, 2023, 10:03 a.m. UTC | #4
On 07.08.23 10:10, Ilya Leoshkevich wrote:
> On Sat, 2023-08-05 at 10:02 +0200, David Hildenbrand wrote:
>> On 05.08.23 01:03, Ilya Leoshkevich wrote:
>>> Currently the emulation of VSTRS recognizes partial matches in
>>> presence
>>> of \0 in the haystack, which, according to PoP, is not correct:
>>>
>>>       If the ZS flag is one and a zero byte was detected
>>>       in the second operand, then there can not be a
>>>       partial match ...
>>>
>>> Add a check for this. While at it, fold a number of explicitly
>>> handled
>>> special cases into the generic logic.
>>
>> Can we split that off? Or doesn't it make sense to split it off after
>> fixing the issue?
> 
> I could do this if this is important, e.g., for stable, but I came to
> the conclusion that I needed to get rid of the special cases after I
> had to add the new check to more than one place.

Okay, so let's keep it as is.

Fortunately you heavily test that code! :)

Acked-by: David Hildenbrand <david@redhat.com>
diff mbox series

Patch

diff --git a/target/s390x/tcg/vec_string_helper.c b/target/s390x/tcg/vec_string_helper.c
index 9b85becdfbf..a19f429768f 100644
--- a/target/s390x/tcg/vec_string_helper.c
+++ b/target/s390x/tcg/vec_string_helper.c
@@ -474,9 +474,9 @@  DEF_VSTRC_CC_RT_HELPER(32)
 static int vstrs(S390Vector *v1, const S390Vector *v2, const S390Vector *v3,
                  const S390Vector *v4, uint8_t es, bool zs)
 {
-    int substr_elen, substr_0, str_elen, i, j, k, cc;
+    int substr_elen, i, j, k, cc;
     int nelem = 16 >> es;
-    bool eos = false;
+    int str_leftmost_0;
 
     substr_elen = s390_vec_read_element8(v4, 7) >> es;
 
@@ -498,47 +498,20 @@  static int vstrs(S390Vector *v1, const S390Vector *v2, const S390Vector *v3,
     }
 
     /* If ZS, look for eos in the searched string. */
+    str_leftmost_0 = nelem;
     if (zs) {
         for (k = 0; k < nelem; k++) {
             if (s390_vec_read_element(v2, k, es) == 0) {
-                eos = true;
+                str_leftmost_0 = k;
                 break;
             }
         }
-        str_elen = k;
-    } else {
-        str_elen = nelem;
     }
 
-    substr_0 = s390_vec_read_element(v3, 0, es);
-
-    for (k = 0; ; k++) {
-        for (; k < str_elen; k++) {
-            if (s390_vec_read_element(v2, k, es) == substr_0) {
-                break;
-            }
-        }
-
-        /* If we reached the end of the string, no match. */
-        if (k == str_elen) {
-            cc = eos; /* no match (with or without zero char) */
-            goto done;
-        }
-
-        /* If the substring is only one char, match. */
-        if (substr_elen == 1) {
-            cc = 2; /* full match */
-            goto done;
-        }
-
-        /* If the match begins at the last char, we have a partial match. */
-        if (k == str_elen - 1) {
-            cc = 3; /* partial match */
-            goto done;
-        }
-
+    cc = str_leftmost_0 == nelem ? 0 : 1;  /* No match. */
+    for (k = 0; k < nelem; k++) {
         i = MIN(nelem, k + substr_elen);
-        for (j = k + 1; j < i; j++) {
+        for (j = k; j < i; j++) {
             uint32_t e2 = s390_vec_read_element(v2, j, es);
             uint32_t e3 = s390_vec_read_element(v3, j - k, es);
             if (e2 != e3) {
@@ -546,9 +519,16 @@  static int vstrs(S390Vector *v1, const S390Vector *v2, const S390Vector *v3,
             }
         }
         if (j == i) {
-            /* Matched up until "end". */
-            cc = i - k == substr_elen ? 2 : 3; /* full or partial match */
-            goto done;
+            /* All elements matched. */
+            if (k > str_leftmost_0) {
+                cc = 1;  /* Ignored match. */
+                k = nelem;
+            } else if (i - k == substr_elen) {
+                cc = 2;  /* Full match. */
+            } else {
+                cc = 3;  /* Partial match. */
+            }
+            break;
         }
     }